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NavigationPolygon¶
Inherits: Resource < RefCounted < Object
A 2D navigation mesh that describes a traversable surface for pathfinding.
Description¶
A navigation mesh can be created either by baking it with the help of the NavigationServer2D, or by adding vertices and convex polygon indices arrays manually.
To bake a navigation mesh at least one outline needs to be added that defines the outer bounds of the baked area.
var new_navigation_mesh = NavigationPolygon.new()
var bounding_outline = PackedVector2Array([Vector2(0, 0), Vector2(0, 50), Vector2(50, 50), Vector2(50, 0)])
new_navigation_mesh.add_outline(bounding_outline)
NavigationServer2D.bake_from_source_geometry_data(new_navigation_mesh, NavigationMeshSourceGeometryData2D.new());
$NavigationRegion2D.navigation_polygon = new_navigation_mesh
var newNavigationMesh = new NavigationPolygon();
var boundingOutline = new Vector2[] { new Vector2(0, 0), new Vector2(0, 50), new Vector2(50, 50), new Vector2(50, 0) };
newNavigationMesh.AddOutline(boundingOutline);
NavigationServer2D.BakeFromSourceGeometryData(newNavigationMesh, new NavigationMeshSourceGeometryData2D());
GetNode<NavigationRegion2D>("NavigationRegion2D").NavigationPolygon = newNavigationMesh;
Adding vertices and polygon indices manually.
var new_navigation_mesh = NavigationPolygon.new()
var new_vertices = PackedVector2Array([Vector2(0, 0), Vector2(0, 50), Vector2(50, 50), Vector2(50, 0)])
new_navigation_mesh.vertices = new_vertices
var new_polygon_indices = PackedInt32Array([0, 1, 2, 3])
new_navigation_mesh.add_polygon(new_polygon_indices)
$NavigationRegion2D.navigation_polygon = new_navigation_mesh
var newNavigationMesh = new NavigationPolygon();
var newVertices = new Vector2[] { new Vector2(0, 0), new Vector2(0, 50), new Vector2(50, 50), new Vector2(50, 0) };
newNavigationMesh.Vertices = newVertices;
var newPolygonIndices = new int[] { 0, 1, 2, 3 };
newNavigationMesh.AddPolygon(newPolygonIndices);
GetNode<NavigationRegion2D>("NavigationRegion2D").NavigationPolygon = newNavigationMesh;
Tutorials¶
Properties¶
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